Re: I'll motivate you
Posted: Thu Mar 18, 2010 5:23 pm
But the full name was long, hard to spell and strange and a reference to a cartoon...
Page 14 of 28
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:10 pm
but cheet is.... oy...
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:11 pm
I think cheech would have been better
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:41 pm
sounds like cheat...
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:43 pm
but I like cheetos... 
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:45 pm
i hate cheese.
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:48 pm
well cheese hates you!
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:54 pm
how did arkie change his name? 
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:56 pm
what do you mean?
Re: I'll motivate you
Posted: Thu Mar 18, 2010 8:57 pm
That's not Arkie, thats cheech
Re: I'll motivate you
Posted: Thu Mar 18, 2010 9:01 pm
wait, isn't arkie everyone? i think that's what he means...
Re: I'll motivate you
Posted: Thu Mar 18, 2010 10:09 pm
I'm not Arkie D: God save me of such a terrible thing!
Re: I'll motivate you
Posted: Thu Mar 18, 2010 11:15 pm
Yes you are.
Re: I'll motivate you
Posted: Thu Mar 18, 2010 11:19 pm
So where did Vrai go then?!... 
Re: I'll motivate you
Posted: Thu Mar 18, 2010 11:20 pm
I'm not arkie, shame on you Cheet if I'm arkie
Re: I'll motivate you
Posted: Thu Mar 18, 2010 11:27 pm
So if Vrai is Arkie, and Cheet is Arkie, but Vrai is not Arkie, and Cheet should be ashamed, that means that Cheet is Vraiment, and Arkie is shamed away!...
Re: I'll motivate you
Posted: Thu Mar 18, 2010 11:38 pm
Very nice conclusion CX, do you study logic?
Re: I'll motivate you
Posted: Fri Mar 19, 2010 12:02 am
Does not make any sense...
Re: I'll motivate you
Posted: Fri Mar 19, 2010 12:23 am
V(x) : x is VraimentCX gamer wrote:So if Vrai is Arkie, and Cheet is Arkie, but Vrai is not Arkie, and Cheet should be ashamed, that means that Cheet is Vraiment, and Arkie is shamed away!...
A(x) : x is Arkie
C(x) : x is Cheet
S(x) : x should be ashamed
{(A[V(x)]^A[C(x)])^~A[V(x)]^S[C(x)]}->{C[V(x)]^S[A(x)]}
That makes a lot of sense to me